题目描述：

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3

Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.

Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000

代码实现：

class Solution {
public:
    int findMaxConsecutiveOnes(vector<int>& nums) {
        int cnt=0,max=0;
        for(int num:nums){
            if(num==1){
                cnt++;
            }else{
                cnt=0;
            }
            max = max>cnt?max:cnt;
        }
        return max;
    }
};